555电路的0.693是怎么来的

核心提示振荡周期等于电容的充电和放电时间之和,充电时间为:T1=(R1+R2)Cln(Vdd-Vdd/3)/(Vdd-2Vdd/3)=0.7(R1+R2)C.同理,放电时间:T2=R2Cln(0-2Vdd/3)/(0-Vdd/3).你说的0.693

振荡周期等于电容的充电和放电时间之和,充电时间为:T1=(R1+R2)Cln(Vdd-Vdd/3)/(Vdd-2Vdd/3)=0.7(R1+R2)C.同理,放电时间:T2=R2Cln(0-2Vdd/3)/(0-Vdd/3).你说的0.693就是充放电时的ln(Vdd-Vdd/3)/(Vdd-2Vdd/3)和ln(0-2Vdd/3)/(0-Vdd/3)得来的。希望能帮到你!

 
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